Calculus
posted by Zach .
The Problem:
The spherical top holds a little over 54,000 gallons of water. The base of the top is 60 feet above the ground. The diameter of the supporting column is onethird the radius of the sphere. The base of the supporting column flares out like a cone (a frustum) so that the diameter of the bottom is equal to the radius of the sphere; this bottom section is 15 feet tall. Likewise, the connection between the support and the sphere (another frustum) flares out to a diameter equal to twothirds the radius of the spehere and is 10 feet tall.
Paint must be applied at an average thickness of .16cm over the entire structure. Calculate how much pain is needed to paint the details (Surface Area of total structure).

Is this math or english