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You shoot a 51-g pebble straight up with a catapult whose spring constant is 320N/m. The catapult is initially stretched by 0.20m. How high above the starting point does the pebble fly? Ignore air resistance.

  • Physics -

    Elastic potential energy=potential energy
    1/2kx^2=mgh
    (0.5)(320)(0.2)^2=(0.051)(9.8)h

    Solve for h
    h=12.8 m

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