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from 4 feet above a swimming pool, susan throws a ball upward witha velocity of 32 feet per second. how long does it take the ball to reach the water?

  • math -

    (Vf)^2 = Vo^2 + 2gd = 0,
    (32)^2 - 2*32d = 0,
    1024 - 64d = 0,
    -64d = -1024,
    d(up) = 16ft.

    Vf = Vo + gt = 0,
    32 - 32t = 0,
    -32t = -32,
    t(up) = 1s.

    d(down) = 4 + 16 = 20ft.

    d = Vo + 0.5gt^2 = 20ft.
    d = 0 + 0.5*32t^2 = 20,
    16t^2 = 20,
    t^2 = 1.25,
    t(down) = 1.12s.

    t(up) + t(down) = 1 + 1.12 = 2.12s =
    time for ball to reach water.

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