How much sodium carbonate is needed to precipitate nickel sulfate
To determine the amount of sodium carbonate needed to precipitate nickel sulfate, we first need to understand the chemical reaction between these two compounds. The equation for the reaction is as follows:
NiSO4 (aq) + Na2CO3 (aq) → NiCO3 (s) + Na2SO4 (aq)
From the equation, we can see that one mole of nickel sulfate (NiSO4) reacts with one mole of sodium carbonate (Na2CO3) to produce one mole of nickel carbonate (NiCO3) and one mole of sodium sulfate (Na2SO4).
To calculate the amount of sodium carbonate required, we need to determine the number of moles of nickel sulfate present.
1. Begin by finding the molar mass of nickel sulfate (NiSO4) and sodium carbonate (Na2CO3):
- Nickel sulfate (NiSO4) has a molar mass of approximately 154.76 g/mol.
- Sodium carbonate (Na2CO3) has a molar mass of approximately 105.99 g/mol.
2. Determine the amount of nickel sulfate (NiSO4) in grams or moles that you have available.
3. Convert the amount of nickel sulfate (NiSO4) into moles by dividing the mass in grams by the molar mass of nickel sulfate (NiSO4).
4. Since the reaction is 1:1, the number of moles of sodium carbonate required will be equal to the moles of nickel sulfate used.
5. Convert the moles of sodium carbonate required into grams by multiplying the number of moles by the molar mass of sodium carbonate (Na2CO3).
By following these steps, you can calculate the precise amount of sodium carbonate needed to precipitate nickel sulfate based on the available mass or moles of nickel sulfate.