An equilibrium mixture contains 2.0cm 3 of 1.00mol dm-3 of h2so4. Calculate the number of moles of H+ in this acid???
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To calculate the number of moles of H+ in the given acid, we need to use the balanced chemical equation for the dissociation of sulfuric acid (H2SO4).
The balanced equation for the dissociation of H2SO4 is as follows:
H2SO4 → 2H+ + SO4^2-
From the equation, we can see that 1 molecule of H2SO4 dissociates to produce 2 H+ ions.
Given:
Volume of H2SO4 = 2.0 cm^3
Concentration of H2SO4 = 1.00 mol dm^-3
To find the number of moles of H+ ions, we can use the following formula:
Number of moles = (concentration × volume) / 1000
First, let's convert the volume of H2SO4 from cm^3 to dm^3:
1 dm^3 = 1000 cm^3
So, 2.0 cm^3 = 2.0 / 1000 dm^3 = 0.002 dm^3
Now, we can substitute the values into the formula:
Number of moles of H+ = (1.00 mol dm^-3 × 0.002 dm^3) / 1000
= 0.002 mol H+
Therefore, the number of moles of H+ in 2.0 cm^3 of 1.00 mol dm^-3 H2SO4 is 0.002 mol.