A cross section of a hollow circular pipe shows that its inner diameter is 2 1/10 inches and that the pipe is 3/5 inch thick. What is its outside diameter?
2 1/10 + 1 1/5
2 1/10 + 1 2/10 = 3 3/10 inches
To find the outside diameter of the hollow circular pipe, we need to add the thickness of the pipe to the inner diameter.
First, let's convert the mixed number 2 1/10 to an improper fraction.
2 1/10 = ((2 * 10) + 1)/10 = 21/10
Now, to find the outside diameter, we need to add the thickness of the pipe (3/5 inch) to the inner diameter (21/10 inches):
21/10 + 3/5
To add these fractions, we need a common denominator, which is the least common multiple of 10 and 5, which is 10.
Rewriting the fractions with a common denominator, we get:
(21/10) + (6/10)
Now, we can add the fractions:
(21 + 6)/10 = 27/10
The sum 27/10 represents the combined inner diameter and thickness of the pipe. To convert this improper fraction to a mixed number:
27/10 = 2 7/10
Therefore, the outside diameter of the hollow circular pipe is 2 7/10 inches.