a.) 2KClO3 (s)-------> 2KCl(s) + 3O2(g)
b.) 4NH3(g) +6NO(g) ---------> 5N2 (g) +6H2O(g)
c.) 4K(s) + O2(g) ------> 2K2O(s)
Do you have a question?
what the answer?
a.) The balanced chemical equation for the reaction is:
2KClO3 (s) → 2KCl(s) + 3O2(g)
To balance this chemical equation, we need to make sure that the number of atoms of each element is the same on both sides of the equation.
We start by counting the number of potassium (K) atoms. There are 2 K atoms on both the reactant side (2KClO3) and the product side (2KCl). This is already balanced.
Next, we count the number of chlorine (Cl) atoms. There are 3 Cl atoms on the reactant side (2KClO3) and 2 Cl atoms on the product side (2KCl). To balance the Cl atoms, we need a coefficient of 3 in front of KCl on the product side.
Finally, we count the number of oxygen (O) atoms. There are 6 O atoms on the reactant side (3O2) and 3 O atoms on the product side (2KClO3). To balance the O atoms, we need a coefficient of 3 in front of O2 on the reactant side.
Therefore, the balanced equation is: 2KClO3 (s) → 2KCl(s) + 3O2(g)
b.) The balanced chemical equation for the reaction is:
4NH3(g) + 6NO(g) → 5N2(g) + 6H2O(g)
To balance this equation, we follow a similar process as before.
Starting with nitrogen (N) atoms, there are 4 N atoms on the reactant side (4NH3) and 10 N atoms on the product side (5N2). To balance the N atoms, we need a coefficient of 5 in front of N2 on the product side.
Next, we count the hydrogen (H) atoms. There are 12 H atoms on the reactant side (6H2O) and 12 H atoms on the product side (6NO + 6H2O). This is already balanced.
Finally, we count the oxygen (O) atoms. There are 6 O atoms on the reactant side (6NO) and 12 O atoms on the product side (6H2O). To balance the O atoms, we need a coefficient of 6 in front of H2O on the reactant side.
Therefore, the balanced equation is: 4NH3(g) + 6NO(g) → 5N2(g) + 6H2O(g)
c.) The balanced chemical equation for the reaction is:
4K(s) + O2(g) → 2K2O(s)
To balance this equation, we follow the same process as before.
Starting with potassium (K) atoms, there are 4 K atoms on the reactant side (4K) and 4 K atoms on the product side (2K2O). This is already balanced.
Next, we count the oxygen (O) atoms. There is 2 O atoms on the product side (2K2O). To balance the O atoms, we need a coefficient of 5 in front of O2 on the reactant side.
Therefore, the balanced equation is: 4K(s) + 5O2(g) → 2K2O(s)