X-radiation from a molybdenum target (0.626 A) is incident on a crystal with adjacent atomic planes spaced 4.00x10(-10) m apart. Find three smallest angles at which intensity maxima occur in the diffracted beam?

The symbol A should have a above it, and means 1 Angstrom unit.

The wavelength is 0.626*10^-8 cm.

Review and use the Bragg equation to get the diffracted beam angles.

http://www.eserc.stonybrook.edu/ProjectJava/Bragg/

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Let's dive into the question, shall we? The diffracted beam occurs when the X-ray radiation interacts with the atomic planes of the crystal. According to Bragg's law, we can calculate the angles at which intensity maxima occur.

The first thing we need to do is to find the wavelength of the X-radiation using the equation:

λ = (h / p) * sin(θ)

Where:
λ is the wavelength of the X-radiation,
h is the Planck's constant (6.626 x 10^(-34) J*s),
p is the momentum of the X-radiation (mass times velocity), and
θ is the angle of incidence.

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Instead of solving the equation step-by-step here, I'll encourage you to plug in the values and calculate the wavelength of the X-radiation. From there, you can use Bragg's law to find the angles at which the intensity maxima occur.

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Keep up the great work, and remember to sprinkle some laughter along your scientific journey!

To find the three smallest angles at which intensity maxima (also known as diffraction maxima) occur in the diffracted beam, we can use Bragg's Law. Bragg's Law states that the condition for constructive interference in crystal diffraction occurs when the path difference between two adjacent planes of atoms is equal to an integer multiple of the wavelength.

The formula for Bragg's Law is given by:

nλ = 2d sinθ

Where:
- n is the order of the diffraction maximum (integer)
- λ is the wavelength of the X-ray radiation
- d is the spacing between adjacent atomic planes in the crystal
- θ is the angle of incidence of the X-ray beam on the crystal

Given the following values:
- λ = 0.626 Å = 0.626 x 10^(-10) m (converted from Angstrom to meters)
- d = 4.00 x 10^(-10) m

We can rearrange Bragg's Law to solve for θ:

θ = arcsin(nλ / 2d)

Substituting the values, we can now calculate the three smallest angles at which intensity maxima occur using n = 1, 2, and 3:

For n = 1:
θ(1) = arcsin((1 x 0.626 x 10^(-10)) / (2 x 4.00 x 10^(-10)))

For n = 2:
θ(2) = arcsin((2 x 0.626 x 10^(-10)) / (2 x 4.00 x 10^(-10)))

For n = 3:
θ(3) = arcsin((3 x 0.626 x 10^(-10)) / (2 x 4.00 x 10^(-10)))

Calculating these values will give us the three smallest angles at which intensity maxima occur in the diffracted beam.

To find the three smallest angles at which intensity maxima occur in the diffracted beam, we can use Bragg's Law. Bragg's Law determines the angles at which constructive interference occurs for X-ray diffraction from a crystal.

Bragg's Law is given by the equation:

2d sinθ = nλ

Where:
- d is the spacing between adjacent atomic planes in the crystal
- θ is the angle of incidence
- n is the order of the diffraction maximum
- λ is the wavelength of the incident X-ray radiation

In this case, we are given:
- d = 4.00x10^(-10) m
- λ = 0.626 Å (angstrom) = 0.626x10^(-10) m

We want to find the three smallest angles (θ) for n = 1, 2, and 3.

We can rearrange Bragg's Law to solve for θ:

θ = arcsin((nλ) / (2d))

Now, we can calculate the three smallest angles:

For n = 1:
θ1 = arcsin((1 * 0.626x10^(-10) m) / (2 * 4.00x10^(-10) m))

For n = 2:
θ2 = arcsin((2 * 0.626x10^(-10) m) / (2 * 4.00x10^(-10) m))

For n = 3:
θ3 = arcsin((3 * 0.626x10^(-10) m) / (2 * 4.00x10^(-10) m))

Now, we can calculate the values using a scientific calculator or computer software with trigonometric functions.