A gas mixture, has a total pressure of 300. Torr and consists of equal masses of Ne and Ar. What is the partial pressure of Ar, in Torr?
I would make up a convenient number (100 for example) and say the gas mixture consists of 100 g Ne and 100 g Ar.
Calculate moles of each.
Calculate total moles.
Calculate mole fraction of each.
Then PAr = mole fraction Ar x 300
PNe = moles fraction Ne x 300 = ??
Post your work if you get stuck.
100
To find the partial pressure of Ar, we need to determine the mole fraction of Ar in the gas mixture. The mole fraction (χ) of a component is the ratio of the number of moles of that component to the total number of moles of all the components in the mixture.
Since the gas mixture consists of equal masses of Ne and Ar, this means that they have the same number of moles. Therefore, the mole fraction of Ar (χAr) is equal to 0.5.
The partial pressure of Ar (PAr) can be calculated using the formula:
PAr = χAr * Ptotal
where Ptotal is the total pressure.
Substituting the given values, we have:
PAr = 0.5 * 300. Torr
= 150. Torr
Therefore, the partial pressure of Ar in the gas mixture is 150. Torr.
To find the partial pressure of Ar in the gas mixture, we need to use Dalton's Law of Partial Pressures. According to this law, the total pressure of a gas mixture is equal to the sum of the partial pressures of its individual components.
In this case, we are given that the total pressure of the gas mixture is 300 Torr and that the mixture consists of equal masses of Ne and Ar. Since the masses are equal, we can assume that the moles of Ne and Ar are the same.
Dalton's Law states that the partial pressure of a component in a gas mixture is equal to the total pressure multiplied by the mole fraction of that component. The mole fraction is the ratio of the number of moles of that component to the total number of moles in the mixture.
Since the moles of Ne and Ar are the same, the mole fraction of Ar is 1/2, as there are two components in the mixture. Therefore, the partial pressure of Ar can be calculated as follows:
Partial pressure of Ar = Total pressure * Mole fraction of Ar
= 300 Torr * (1/2)
= 150 Torr
So, the partial pressure of Ar in the gas mixture is 150 Torr.