Hi! Today I was absent from my algebra class, and they learned how to recognize and factor the difference of two squares..

I've tried to figure it out from the book, but it's not making any sense...
Can someone help?
I'm trying to figure out this problem
1 - 4x^2

You have to plug 4x^2 into the square root. the answer is 2x because the square root of 4 is 2 and then the x just stays with the 2.

The difference of two squares can be expressed by

(x^2 - y^2) = (x + y)(x - y)

1 - 4x^2 is therefore expressible as
(1 + 2x)(1 - 2x)

Of course, I can help you with that!

To recognize and factor the difference of two squares, like in the expression 1 - 4x^2, you need to look for the following pattern: "a^2 - b^2".

In this case, we have 1 - 4x^2. The first step is to identify the squares. In this case, we have (1)^2 and (2x)^2.

Now that we have identified the squares, we can apply the formula to factor the difference of two squares: "a^2 - b^2 = (a + b)(a - b)".

Using this formula, we can rewrite 1 - 4x^2 as (1 + 2x)(1 - 2x).

So, the factored form of the expression 1 - 4x^2 is (1 + 2x)(1 - 2x).

Remember to always double-check your factored form by multiplying it back to ensure you get the original expression.

If you have any further questions, feel free to ask!