chemistry

posted by .

What is the pH of a solution with [H+]= 4.75 x 10^-5?
I set this up as:
pH= -log[H+]
=-log (4.75 x 10^-5)
= 4.32

Is this the correct to solve this? thanks

  • chemistry -

    Yes, and 4.32 is the correct answer.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. TRig WIth LoGs help1!!

    i have problem i can't solve and the book is no help.. anyone got osme hints or somehting i could start off doing?
  2. Math Exam Tuesday

    My friend swears by your site so I thought I'd confirm some of my more difficult answers for my math practice exam. Is the solution set for 8^x = 16^ x+2 is it -2?
  3. math

    solve for x without using a calculator 5^(x+1) = 25 i know that x would equal 1 because 5^2 is 25, but i don't know how to show how to solve it All you need to do is what you just did: Explain that if x = 1, the equation is satisfied. …
  4. Mathematics

    Prove that log a, log ar, log ar^2 is an a.p. Is the following below correct?
  5. Math Help Please

    Which of the following expressions is equal to log (x sqrt-y)/z^5 A. log x + log (1/2) + log y– log 5 – log z B. log [x + (1/2)y – 5z] C. log x + (1/2)log y – 5 log z d. [(1/2) log x log y]/(5 log z)
  6. math

    Logarithm!!! Select all of the following that are true statements: (a) log(2x) = log(2) + log(x) (b) log(3x) = 3 log(x) (c) log(12y) = 2 log(2) + log(3y) (d) log(5y) = log(20y) – log(4) (e) log(x) = log(5x) – log(5) (f) ln(25) …
  7. Math

    Find the exact solution, using common logarithms, and a two-decimal-place approximation of each solution. log(7x + 4) = 2 + log(2x − 3) Solve the equation. log(x^3) = (log x)^2
  8. Advanced Functions/ Precalculus Log

    1. Evaluate 4^(log base4 64) + 10^(log100) 2. Write 1+log(base2)x^3 as a single logarithm 3. Write log(base b)√(x^3 y z^6) 4. Solve log(base 2)x-log(base 2)6=log(base 2)5+2log(base 2)3 5. Solve 3^(2x) = 9(81^x) 6. Solve 3^(2x)=7^(3x-1). …
  9. Math

    h(x) = log (6x+5/7x-4) Find a formula for the inverse function h^-1(x) h^-1(x) = My work so far h(x) = log(6x+5/7x-4) y=log(6x+5/7x-4) x=log(6y+5/7y-4) 7xy-4x= log(6y+5) how would I solve from here. Would I solve for y then do the …
  10. Calculus AB

    How do you solve a system of logarithmic equations?

More Similar Questions