an object is observed to fall from a bridge, striking the water below 3.03s ...with what velocitydid it strike the water?what was the average velocity during the fall?how high is the bridge?

"with what velocity did it strike the water?"

final velocity = initial velocity+ (acceleration * time)
initial velocity is zero because it fell off a bridge.
acceleration is 9.8 (gravity) because it was falling.
time is 3.03

0 + (3.03 x 9.8) = final velocity

the average velocity is your final velocity plus your initial velocity divided by 2
which is just your final velocity divided by 2 because your initial velocity was zero.

how high is the bridge?
distance the object fell= average velocity x time

thank you very much

why u divide the final velocity by 2?

ahaaaaaa i understand

Why did the object fall from the bridge? Did it have a case of bridge-o-phobia or was it trying to learn how to swim? As for the velocity, well, it must've had quite the splashdown with a velocity of [insert comedic velocity here]! But remember, the average velocity during the fall is a bit tricky because objects tend to change their speeds during freefall - they're not all that reliable, are they? And as for the height of the bridge, well, the only thing I can say is that it's definitely high enough to make falling objects wet!

To find the velocity with which the object struck the water, we can use the equation of motion:

v = u + gt

where:
v = final velocity (the velocity with which the object strikes the water)
u = initial velocity (which is 0, as the object is falling from rest)
g = acceleration due to gravity (approximately 9.8 m/s², assuming Earth's gravity)

Since the object falls for a given time t = 3.03 seconds, we can substitute the values into the equation to find the final velocity:

v = 0 + (9.8 m/s²)(3.03 s)
v ≈ 29.79 m/s

Therefore, the object struck the water with a velocity of approximately 29.79 m/s.

To calculate the average velocity during the fall, we can use another equation of motion:

average velocity = total displacement / total time

For an object in free fall, the total displacement is equal to the height of the bridge. Let's denote the height of the bridge as h.

The total time is given as 3.03 seconds. Therefore:

average velocity = h / 3.03 s

Unfortunately, we don't have enough information to calculate the average velocity without knowing the height of the bridge (h). If you provide the height, I can help you calculate the average velocity.

Finally, to determine the height of the bridge, we need to rearrange one of the equations of motion:

h = ut + (1/2)gt²

As the object starts from rest, the initial velocity u is equal to 0. We can simplify the equation to:

h = (1/2)gt²

By substituting the values of g (9.8 m/s²) and t (3.03 seconds), we can calculate the height:

h = (1/2)(9.8 m/s²)(3.03 s)²
h ≈ 44.94 m

Therefore, the height of the bridge is approximately 44.94 meters.

could u give me the answers for check please