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can you please help me solve this problem if dy/dx=ycosx and y=3 when x=0, then y=

  • calculus -

    dy/dx = y cos(x)
    dy/y = cos(x) dx
    ln y + const = sin(x) + const
    ln y = sin(x) + const

    ln 3 = sin(0) + const
    const = ln 3

    ln y = sin(x) + ln 3
    ln y - ln 3 = sin(x)
    ln (y/3) = sin(x)
    y/3 = e^sin(x)
    y = 3e^sin(x)

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