Post a New Question

Chemistry

posted by .

I have 5.0 ml of lead II NITRATE and mix it with 20.0 ml of Sodium Iodide. what is the formula of the precipitate

  • Chemistry -

    PbI2(s) if the concns are high enough.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Chemistry

    A reaction was run where lead nitrate and potassium iodide were mixed. The resulting precipitate only gave a 78.1% yield. If the actual yield was 25.0grams, how many grams of lead nitrate were used?
  2. chemistry

    Stoichiometry 0.083grams of lead nitrate, Pb(NO3)2, in solutions mixed with 0.300g of sodium iodide in solution. This results in the formation of a yellow precipitate of lead iodide. Calculate the weight of the precipitate.
  3. chemistry

    if 5liters of hydrogen iodide gas is bubbled through 2 liters of 0.0275 M lead 2 nitrate solution at STP, how many grams of lead 2 iodide will precipitate out?
  4. Chemistry

    If 32.0 mL lead(II) nitrate solution reacts completely with excess sodium iodide solution to yield 0.545 g precipitate, what is the molarity of lead(II) ion in the original solution?
  5. chemistry

    predict the outcome of mixing aqueous solutions of the following reactions. write the ionic equations of each. mercury (ll) nitrate + ammonium iodide manganese (ll) chloride + sodium sulfide lead (ll) nitrate + sodium sulfate barium …
  6. Chemistry

    In experiment of silver, lead and mercury(I) chlorides mix with NH3, how does the heating of the lead precipitate present after the addition of NH3help identify the formula ?
  7. chemistry

    Sodium fluoride and lead nitrate are both soluble in water. If 1.13 g of NaF and 0.232 g of Pb(NO3)2 are dissolved in sufficient water to make 1.00 L of solution, will a precipitate form?
  8. Chemistry

    A solution containing excess lead(ii) nitrate is reacted with 380.0ML of 0.250mol/L potassium iodide solution. A bright yellow Precipitate is of lead(ii) iodide is formed. Calculate the mass of lead (ii) iodide that should be formed. …
  9. Chemistry

    We can precipitate out solid lead(II) iodide from an aqueous lead(II) nitrate solution by adding potassium iodide. If we have 500. mL of 0.632 M lead(II) nitrate solution and add excess potassium iodide, how much solid lead(II) iodide …
  10. Chemistry

    I'm sorry here is another I do not understand. How do you find out exactly how much of a solution you would need to completely precipitate another compound in the reaction?

More Similar Questions

Post a New Question