8s^2-7t=0
Am I correct saying 2 real numbers?
To determine if the equation 8s^2 - 7t = 0 has real solutions, you can analyze the discriminant of the equation. The discriminant is the part of the quadratic formula under the square root sign and is given by b^2 - 4ac for an equation in the form of ax^2 + bx + c = 0.
In this case, the equation is 8s^2 - 7t = 0. Since it does not have the "x" variable, we can assign "s" as the variable and treat "t" as a constant. Comparing it to ax^2 + bx + c = 0, we have a = 8, b = 0, and c = -7t.
Now, calculating the discriminant:
Discriminant = b^2 - 4ac
Discriminant = 0^2 - 4(8)(-7t)
Discriminant = 0 + 224t
Discriminant = 224t
To determine if the equation has real solutions, we need the discriminant (224t) to be greater than or equal to zero. This means:
224t >= 0
t >= 0
Therefore, if t is greater than or equal to zero, the equation 8s^2 - 7t = 0 will have real solutions.