Please heeelp!!!
A 65.0 kg diver is 2.10 m above the water, falling at speed of 6.70 m/s. Calculate her kinetic energy as she hits the water. (Neglect air friction)
To calculate the kinetic energy of the diver as she hits the water, we can use the formula:
Kinetic energy = 0.5 * mass * velocity^2
Given:
- Mass of the diver (m) = 65.0 kg
- Velocity of the diver (v) = 6.70 m/s
First, let's calculate the gravitational potential energy (PE) of the diver when she is 2.10 m above the water. The formula for gravitational potential energy is:
PE = mass * gravity * height
Where:
- Gravity (g) is the acceleration due to gravity, approximately 9.8 m/s^2
- Height (h) is the distance above the reference point (in this case, the water surface)
Plugging in the values:
PE = 65.0 kg * 9.8 m/s^2 * 2.10 m
PE = 1323.3 J
Since the diver is falling, the gravitational potential energy is converted to kinetic energy. So, the kinetic energy of the diver as she hits the water is equal to the gravitational potential energy:
Kinetic energy = 1323.3 J
Therefore, the kinetic energy of the diver as she hits the water is 1323.3 Joules.
additional KE gained in last 2.1m = mgh
total KE at water= mg(2.10)+1/2 m (6.7)^2
now from total KE, solve for v