calculus
posted by mike .
solve the initial value problem by seperation of variables du/dt=2t+sec2t/2u, u(0)=5

The following equation is separable (please check this is the same as your question after adding appropriate parentheses):
du/dt = (2t+sec(2t)) / (2u)
transpose terms to get:
(2u)du = (2t+sec(2t))dt
Integrate both sides (do not forget the integration constant) and substitute u(0)=5 (i.e. u(t)=5, when t=0) to evaluate the integration constant.
Post your answer for a check if you wish.
Respond to this Question
Similar Questions

calculus
solve the initial value problem by separation of variables dy/dx=y^(2)+1, y(1)=0 
calculus
solve the initial value problem by separation of variables 8. dy/dx=x+1/xy, x>0, y(1)=4 
calculus
solve the initial value problem by seperation of variables du/dt=2t+sec2t/2u, u(0)=5 
calculus
how do you solve the initial value problem by using separation of variables dy/dx=1/y^2, y(0)=4 
calculus
solve the initial value problem by separation of variables dy/dx=x^2y^2, y(4)=4 
calculus
solve the initial value problem by separation of variables dy/dx=xy^2, y(1)=0.25 
calculus
solve the initial value problem by separation of variables dy/dx=xy^2, y(1)=0.25 
calculus
solve the initial value problem by separation of variables dy/dx=x^2y^2, y(4)=4 
calculus
how do you solve the initial value problem by separation of variables dy/dx=x^2y^2, y(4)=4 
calculus
how do you solve the initial value problem by using separation of variables dy/dx=xy^2 when y(1)=0.25