what is the Molecular equation for the preparation of tetra-aminocopper(II)sulfate hydrate - Cu(NH3)4SO4*H20
in the experiment CuSO4*5H20 was added to water and then ammonia solution was added to that. and then after that was all stirred up nicely 95% ethanol was added to the mix. im just really confused on where to get my molecular equation from
To determine the molecular equation for the preparation of tetra-aminocopper(II)sulfate hydrate (Cu(NH3)4SO4·H2O), we need to understand the reactions that occur during the preparation process. Let's break it down step by step:
1. Start with Copper(II) sulfate pentahydrate (CuSO4·5H2O):
CuSO4·5H2O + H2O (water) → CuSO4·6H2O
Here, by dissolving CuSO4·5H2O in water, it gains one more water molecule, resulting in CuSO4·6H2O.
2. Add excess ammonia solution (NH3) to form tetra-aminocopper(II)sulfate:
CuSO4·6H2O + 4 NH3 → Cu(NH3)4SO4·6H2O
Ammonia replaces the water molecules in copper sulfate, forming the tetra-aminocopper(II)sulfate complex. The "4" in Cu(NH3)4SO4 represents the four ammonia molecules coordinated with copper.
3. Finally, add 95% ethanol (C2H5OH):
Cu(NH3)4SO4·6H2O + 6 H2O + C2H5OH → Cu(NH3)4SO4·H2O + H2SO4 + C2H5OH
The ethanol acts as a solvent and aids in the crystallization of the tetra-aminocopper(II)sulfate hydrate. Upon evaporation, the product, Cu(NH3)4SO4·H2O, forms along with sulfuric acid (H2SO4).
So, the overall molecular equation for the preparation of tetra-aminocopper(II)sulfate hydrate is:
CuSO4·5H2O + H2O + 4 NH3 + 6 H2O + C2H5OH → Cu(NH3)4SO4·H2O + H2SO4 + C2H5OH