chemistry

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A 0.040M solution of a weak acid has a pH of 3.02 at 25°C . What is the value of Ka for the acid?

  • chemistry -

    ...............HA ==> H^+ + A^-
    begin.........0.04M....0......0
    change..........-x......+x.....+x
    final.......0.04-x......x.......x
    Ka = (H^+)(A^-)/(HA)
    You know pH, convert to (H^+) and that will be x. Substitute into Ka expression and solve for Ka.

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