Aluminum Chloride has a universal indicator color of red and the Ph of 4.0

b) Sodium Carbonate has a universal indicator color of violet and the Ph of 9.5.
c) Ammonium Acetate has a universal indicator color of green and the Ph of 7.5

For the following salts give an explanation of these salts should have these Ph with an equation to show Hydrolysis????

Please read your post; perhaps you will see why no one is answering. You ask about "the following salts" but you don't list any salts.

Aluminum Chloride has a universal indicator color of red and the Ph of 4.0

b) Sodium Carbonate has a universal indicator color of violet and the Ph of 9.5.
c) Ammonium Acetate has a universal indicator color of green and the Ph of 7.5 ....For the following salts AlCl3, Na2CO3, C2H7NO2 give an explanation of these salts should have these Ph with an equation to show Hydrolysis????

See your post above. I wrote the hydrolysis equation which explains why Na2CO3 is basic in solution due to hydrolysis.

To determine why these salts have specific pH values and whether they undergo hydrolysis, we need to consider their chemical composition and their reaction with water.

a) Aluminum Chloride (AlCl3):
Aluminum chloride is an inorganic salt that contains aluminum and chloride ions. When dissolved in water, it dissociates into aluminum cations (Al3+) and chloride anions (Cl-). This salt does not undergo hydrolysis, meaning it does not react significantly with water to produce acidic or basic ions.

Therefore, the pH of aluminum chloride solution depends on the hydrolysis of water itself. Pure water is neutral with a pH of 7. Since the pH of aluminum chloride is 4.0 (indicating acidity), it means that hydrolysis of water is slightly suppressed, making the solution more acidic.

The equation for the dissociation of aluminum chloride in water is:
AlCl3 → Al3+ + 3Cl-

b) Sodium Carbonate (Na2CO3):
Sodium carbonate is an inorganic salt that contains sodium cations (Na+) and carbonate anions (CO3^2-). In water, it dissociates into these ions. Carbonate ions can react with water to form bicarbonate ions (HCO3-) and hydroxide ions (OH-) through hydrolysis reactions. The hydroxide ions result in an increase in OH- concentration and make the solution basic.

The equation for the hydrolysis of carbonate ion and formation of bicarbonate ion is:
CO3^2- + H2O ↔ HCO3- + OH-

This reaction increases the concentration of hydroxide ions, resulting in a violet color on the universal indicator scale. Hence, sodium carbonate solution has a pH of 9.5.

c) Ammonium Acetate (NH4C2H3O2):
Ammonium acetate is an organic salt containing ammonium cations (NH4+) and acetate anions (C2H3O2-). When dissolved in water, it dissociates into ammonium ions and acetate ions. Ammonium ion can undergo a hydrolysis reaction with water to produce hydronium ions (H3O+), resulting in an acidic solution.

The equation for hydrolysis of ammonium ion and the formation of hydronium ions is:
NH4+ + H2O ↔ H3O+ + NH3

The presence of hydronium ions makes the solution acidic, which corresponds to the green color on the universal indicator scale. Therefore, ammonium acetate solution has a pH of 7.5.

Note: Hydrolysis is the reaction of a compound with water, resulting in the formation of ions and a change in pH. It is important to consider the specific chemical properties of each salt to determine if hydrolysis occurs and its effect on the pH.