At t= 1.0s, a 0.61 kg object is falling with a speed of 6.0 m/s. At t= 2.0s, it has a kinetic energy of 25 J.
1. What is the kinetic energy of the object at t= 1.0s?
2. What is the speed of the object at t= 2.0s?
3. How much work was done on the object between t= 1.0s and t= 2.0s?
Where are you stuck on this?
never mind, i figured out how to do this problem
1. K = 11J
2. v = 9.1m/s
3. W = 14J
the wording was just alittle bit confusing
I'm actually trying to do this problem right now. I'm a bit stuck on the second part. How do you find the speed of the object at t = 2.0s?
Every kinematic equation I've tried to use requires acceleration, and I can't find acceleration with having the final velocity... ahhh.
To answer these questions, we need to understand the equations and concepts related to kinetic energy and work.
1. Kinetic Energy (KE) = (1/2) * mass * velocity^2
To find the kinetic energy at t=1.0s, we are given the mass (0.61 kg) and speed (6.0 m/s). Substitute these values into the equation:
KE = (1/2) * 0.61 kg * (6.0 m/s)^2
Solve this equation to find the answer.
2. The speed of the object at t=2.0s is not given directly. However, we can use the information about the kinetic energy at that time to find the speed.
We are given that the kinetic energy at t=2.0s is 25 J.
Rearrange the kinetic energy equation to solve for velocity:
KE = (1/2) * mass * velocity^2
25 J = (1/2) * 0.61 kg * velocity^2
Solve this equation to find the speed.
3. Work (W) = change in kinetic energy (ΔKE)
The work done on the object between t=1.0s and t=2.0s can be calculated by finding the change in kinetic energy.
ΔKE = KE2 - KE1
Substitute the values of the kinetic energy at t=1.0s and t=2.0s into the equation:
ΔKE = 25 J (KE at t=2.0s) - (KE at t=1.0s)
Solve this equation to find the work done.