A grander want to create a triangular garden in the shape of a right triangle with shortest side length x-6y ft. and the middle length side x + 6y ft. what is an algebraic expression for the area of the garden? Be sure to multiply this out and express in simplest correct mathematical form, including units.

Granders have to know math, especially the exponential growth equations.

area= (x-6y)(x+6) * 1/2
= (x^2-36y^2)/2 ft^2

Find the quotient: 9a^2 – 100b^2 / 3a – 10b

and the quotient: 6x^3 + 5x^2 + 2x +1 / 2x +3

6. Essay: Show all work. A gardener wants to create a triangular garden in the shape of a right triangle with shortest side length x – 4y ft. and the middle length side x + 6y ft. What is an algebraic expression for the area of the garden? Be sure to multiply this out and express in simplest correct mathematical form, including units.

To find the algebraic expression for the area of the triangular garden, we need to use the formula for finding the area of a right triangle.

The formula for the area (A) of a right triangle is given by the product of the two legs divided by 2: A = (base × height) ÷ 2.

In this case, the two legs of the right triangle are given as follows:
- The shortest side length: x - 6y ft.
- The middle length side: x + 6y ft.

Now, we can substitute these values into the formula to find the area:

A = ((x - 6y) × (x + 6y)) ÷ 2

Next, we can simplify this expression by expanding and multiplying out the terms:

A = (x^2 + 6xy - 6xy - 36y^2) ÷ 2

Simplifying further, we can see that the 6xy and -6xy terms cancel each other out:

A = (x^2 - 36y^2) ÷ 2

And finally, we can express the algebraic expression for the area in the simplest correct mathematical form, including units:

A = (x^2 - 36y^2) / 2 ft^2.

So, the algebraic expression for the area of the garden is (x^2 - 36y^2) / 2 ft^2.