# chemistry

posted by .

4.72 moles of sulfur trioxide molecules contain how many oxygen atoms?

i know the answer is 8.53 x 10^24
but i do know how my professor got it

**this is one of my practice exam question!

• chemistry -

1 mol of a molecule contains 6.022E23 molecules. You have 4.72 moles; therefore,
4.62 x 6.022E23 = 2.842E24 molecules of SO3. There are 3 atoms of oxygen per 1 molecule of SO3; therefore, the number of oxygen atoms must be 3 times that or
2.842E24 x 3 = 8.527E24 which rounds to 8.53E24 to 3 significant figures.

## Similar Questions

1. ### chemistry

how many moles of oxygen atoms does 1.2x10^25 diphosphorus pentoxide molecules have?
2. ### chemistry

Sulfer trioxide, SO3, is made industrially in enormous quantities by combining oxygen and sulfer dioxide, SO2. What amount (moles) of SO3 is represented by 1.00 kg of sulfur trioxide?
3. ### Chemistry

when sulfur is burned in the presence of oxygen, sulfur trioxide is produced. if 3.4 x 10^24 atoms of sulfur react, how many liters of sulfur trioxide are produced?
4. ### chemistry

if you have 0.454 grams of sulfur trioxide, how many moles does this represent?
5. ### chemistry

if 7.o moles of sulfur atoms and 10 moles of oxygen molecules are combined to form the maximum amount of sulfur trioxide, how many moles of which reactant remain unused at the end?
6. ### Chemistry

The gas sulfur dioxide, SO2, oxidizes to form another gas, sulfur trioxide, SO3. How many oxygen atoms are present in 3.20 g of sulfir trioxide?
7. ### Chemistry

At 627ÂșC, sulfur dioxide and oxygen gases combine to form sulfur trioxide gas. At equilibrium, the concentrations for sulfur dioxide, oxygen, and sulfur trioxide gases are .0060M, .0054M, and .0032M, respectively. a. Write a balanced …
8. ### chemistry

how many molecules are in 5.5 moles of oxygen gas?
9. ### Chemistry

Sulfur dioxide (SO2) reacts with oxygen gas to make sulfur trioxide (SO3). How many grams of oxygen are used to produce 8.11 grams of sulfur trioxide?
10. ### Chemistry

Sulfur dioxide reacts with oxygen to form sulfur trioxide according to the equation 2SO2(g) + O2(g) <-> 2SO3(g) Samples of sulfur dioxide, oxygen, and sulfur trioxide were added to a flask of volume 1.40 dm^3 and allowed to reach …

More Similar Questions