if 50 g of HCL is dissolved in 100 g of water at 40 C, how much HCL must be added to the solution in order to saturate it?
the answer is about 12g but can you explain how to get this answer?
thanks.
Without a table or a graph of the solubility of HCl @ 40 C I can't help. I looked on the web but found no info on that.
To find out the amount of HCl required to saturate the solution, we first need to determine the solubility of HCl in water at 40°C. Solubility refers to the maximum amount of solute that can dissolve in a given quantity of solvent under specific conditions.
In this case, we know that 50 g of HCl has already been dissolved in 100 g of water at 40°C. To saturate the solution, we need to add more HCl until no more can dissolve.
To determine the solubility of HCl at 40°C, we can refer to a solubility table or use experimental data. Let's assume that the solubility of HCl at 40°C is 36 g/100 g of water.
We have already dissolved 50 g of HCl in 100 g of water, so we can calculate the amount of additional HCl required to saturate the solution as follows:
Total amount of water in the solution = initial amount of water (100 g) + additional amount of water (0 g) = 100 g
Total amount of HCl required = solubility of HCl (36 g) - initial amount of HCl (50 g) + additional amount of HCl
Therefore, we have:
36 g/100 g = (50 g + additional amount of HCl)/100 g
Using cross-multiplication:
36 g * 100 g = (50 g + additional amount of HCl) * 100 g
3600 g = 50 g + additional amount of HCl
Solving for additional amount of HCl:
additional amount of HCl = 3600 g - 50 g = 3550 g
Therefore, approximately 3550 g of HCl must be added to the solution to saturate it.