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posted by math Monday, March 14, 2011 at 10:00pm.

how do i solve this 2 ln(x-3)= ln(x+5) + ln4

Use the laws of logarithm: ln a + ln b = ln ab 2ln a = ln a² 2 ln(x-3)= ln(x+5) + ln4 => ln(x-3)² = ln 4(x+5) Raise to power of e: (x-3)² = 4(x+5) Simplify and factor to get: (x-11)*(x+1)=0 Can you take it from here?

yes thank you much! :)

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