# amy

posted by .

how do i solve this

2 ln(x-3)= ln(x+5) + ln4

• amy -

Use the laws of logarithm:
ln a + ln b = ln ab
2ln a = ln a²

2 ln(x-3)= ln(x+5) + ln4
=>
ln(x-3)² = ln 4(x+5)
Raise to power of e:
(x-3)² = 4(x+5)
Simplify and factor to get:
(x-11)*(x+1)=0
Can you take it from here?

• amy -

yes thank you much! :)

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