A 10.00g sample of a mixture of CH4 and C2H4react with O2
To determine how the mixture of CH4 and C2H4 reacts with O2, we need to consider their balanced chemical equations.
1. Start by writing the balanced chemical equation for the combustion of methane (CH4) with oxygen (O2):
CH4 + 2O2 -> CO2 + 2H2O
This equation shows that one molecule of methane reacts with two molecules of oxygen to produce one molecule of carbon dioxide and two molecules of water.
2. Now, let's write the balanced chemical equation for the combustion of ethene (C2H4) with oxygen:
C2H4 + 3O2 -> 2CO2 + 2H2O
This equation shows that one molecule of ethene reacts with three molecules of oxygen to produce two molecules of carbon dioxide and two molecules of water.
By comparing the two equations, we can see that methane requires less oxygen to produce the same amount of carbon dioxide and water as ethene.
To determine the specific reaction taking place in your mixture, we need additional information, such as the amount of CH4 and C2H4 present in the mixture. With this information, we can calculate the molar ratios and determine the limiting reactant.
If you provide the specific amount of CH4 and C2H4 in the mixture, I can guide you further on how to calculate the reaction.