26.5 moles of a .2 M aqueous solution of NaOH is required to titrate 50 ml of an aqueous solution of HNO3, what is the concentration of HNO3. I don't want the answer, I want to know how to do it.
To find the concentration of HNO3 in the given titration, we can use the concept of stoichiometry. Here's how you can calculate it:
1. Begin by writing the balanced chemical equation for the reaction between NaOH and HNO3. In this case, the balanced equation is:
NaOH + HNO3 → NaNO3 + H2O
2. Determine the stoichiometric ratio between NaOH and HNO3 in the balanced equation. From the equation, we can see that the ratio is 1:1. Therefore, 1 mole of NaOH reacts with 1 mole of HNO3.
3. Convert the number of moles of NaOH used in the titration to moles of HNO3. Since the stoichiometric ratio is 1:1, the number of moles of HNO3 will be the same as the number of moles of NaOH used. In this case, it is given that 26.5 moles of NaOH was used.
4. Calculate the volume of HNO3 using the known number of moles of NaOH and the molarity of the NaOH solution. The formula to use is:
Moles = Molarity × Volume
Since you have calculated the moles in step 3, rearrange the formula to solve for volume:
Volume = Moles / Molarity
In this case, you are given that the molarity of the NaOH solution is 0.2 M. Substitute the values into the formula to get the volume of HNO3.
5. Finally, divide the volume of HNO3 obtained in step 4 (in liters) by the initial volume of the HNO3 solution (50 ml, which should be converted to liters by dividing by 1000) to obtain the concentration of HNO3 in M.
Concentration = Volume HNO3 / Volume HNO3 solution
By following these steps, you will be able to calculate the concentration of HNO3 in the given titration.