Calculus (fixed the typo )

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A line rotates in a horizontal plane according to the equation theta=2t^3 -6t,where theta is the angular position of the rotating line, in radians ,and t is the time,in seconds. Determine the angular acceleration when t=2sec.

A.) 6 radians per sec^2
B.) 12 radians per sec^2
C.) 18 radians per sec^2
D.) 24 radians per sec^2 << my choice.

  • Calculus (fixed the typo ) -

    θ=2t^3-6t

    θ'=dθ/dt=6t²-6

    θ"=d²θ/dt²
    =12t

    θ(2)=12*2=24 radians-sec-2

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