what are the steps to solve for x
2x^2-1/x^2=0
2 x^2 - 1/x^2 = 0 ???
2 x^4 = 1
x^4 = 1/2
x^2 = (1/2)^.5 or -(1/2)^.5
x = (1/2)^.25 or -(1/2)^.25 or i(1/2)^.25 or -i(1/2)^.25
thank you.i am trying to sove for critical numbers. the book is giving me an answer of
x=+square root 2/2
-
I am wondering if the problem then is this:
(2x^2-1)/x^2=0
2x^2=1
x= +- sqrt (1/2)
but of course, multiplying that by sqrt(2/2) one gets
x= +- sqrt (2/4)= +- .5 sqrt 2
To solve the equation 2x^2 - 1/x^2 = 0, follow these steps:
Step 1: Multiply through by x^2 to eliminate the denominator:
2x^2(x^2) - 1 = 0
Step 2: Simplify the equation by distributing the x^2 to each term:
2x^4 - 1 = 0
Step 3: Add 1 to both sides of the equation to isolate the term with x^4:
2x^4 = 1
Step 4: Divide both sides of the equation by 2 to solve for x^4:
x^4 = 1/2
Step 5: Take the fourth root of both sides of the equation to solve for x:
x = ±(1/2)^(1/4)
So the solution for x is x = ±(1/2)^(1/4).