in 1993, the life expectancy of males in a certain country was 68.6 yrs. in 1997, it was 71.0 . the linear function that fits the data is what
Isn't your subject math??
Here is your identical question
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look at the last part of the reply.
In 1993, the life expectancy of males in a certain country was 67.6 years. In 1999, it was 71.2 years. Let E represent the life expectancy in year t and let t represent the number
To find the linear function that fits the given data, we need to find the equation of a line in the form of y = mx + b, where y is the dependent variable (life expectancy in this case), x is the independent variable (years), m is the slope, and b is the y-intercept.
Let's assign the year 1993 to x = 0 and the year 1997 to x = 4. Then, we can use the given life expectancies to find the slope.
First, calculate the change in life expectancy: Δy = 71.0 - 68.6 = 2.4.
Next, calculate the change in years: Δx = 4 - 0 = 4.
Now, we can find the slope (m) using the formula: m = Δy / Δx.
m = 2.4 / 4 = 0.6.
Once we have the slope, we can find the y-intercept (b) by substituting the slope and any given data point (x, y). Let's use the point (0, 68.6) from the year 1993.
Using the formula y = mx + b, we can write:
68.6 = 0.6 * 0 + b.
Since anything multiplied by 0 is 0, this equation simplifies to:
68.6 = b.
Therefore, the y-intercept (b) is 68.6.
Now, we can write the linear function that fits the data as:
y = 0.6x + 68.6.
Therefore, the linear function is y = 0.6x + 68.6.