Algebra 2
posted by Esther .
Subtract. Simplify by removing a factor of 1 when possible.
(9p^b)/p^2b^2  pb/p+b.
Thank you. These problems, I don't understand at all. I'm sorry.

The way the expression is typed is probably different from the book for lack of parentheses. When it is typeset, parentheses are not required on the numerator and denominator. When interpreted on one single line, they are required, or else a completely different expression results.
Also, I think 9p^b at the beginning should read 9p^2 (just a guess).
Please check what I assume is the correct interpretation.
(9p^2)/(p^2b^2)  (pb)/(p+b)
=(9p^2)/((p+b)(pb))  (pb)²/((p+b)(pb))
=(9p^2(pb)²)/((p+b)(pb))
=(3p+pb)(3p(pb))/((p+b)(pb))
=(4pb)(2p+b)/((p+b)(pb))