calculus
posted by Anonymous .
Find the area of the region bounded by the graphs f(x)=sqrt(3x)+1, g(x)=x+1

Did you make a sketch?
first find their intersection.
I had them intersect at (0,1) and (3,4)
Area = [integral] ((3x)^(1/2) + 1  x  1) from 0 to 3
= ((2/9(3x)^(3/2)  x^2/2) from 0 to 2
= (2/9)(9)^(3/2)  9/2  (00))
= (2/9)(27)  9/2
= 6  9/2 = 3/2