A person notices a mild shock if the current along a path through the thumb and index finger of one hand exceeds 80 ìA.
In volts, calculate the maximum allowable potential for a hand with moist skin with a resistance of 67.7 kÙ.
please help i am getting the wrong answer.why does it says exceeds 80 micro amperes?
The units you select must be compatible:
V = IR = 80uA * 0.0677 Megohms = 5.42 Volts.
V = 0.08mA * 67.7K Ohms = 5.42 Volts.
V = 80*10^-6Amps * 67.7*10^3 Ohms = 5.42 Volts.
Well, it seems like someone is getting a shocking experience! Let's crunch some numbers and try to find the maximum allowable potential.
First, let's convert the resistance to ohms:
67.7 kÙ = 67.7 x 1000 Ù = 67,700 Ù
Now, we can use Ohm's Law to find the maximum allowable potential (V):
V = I x R
Since the current (I) is given as 80 ìA, we need to convert it to amperes by dividing it by 1,000,000:
80 ìA = 80 x 10^(-6) A = 0.00008 A
Now we can substitute the values into the equation:
V = 0.00008 A x 67,700 Ù
Calculating this, we find:
V ≈ 5.416 volts
So, to avoid exceeding 80 ìA and getting a mild shock, the maximum allowable potential for a hand with moist skin and a resistance of 67.7 kÙ should be approximately 5.416 volts.
Now, why does it say "exceeds 80 micro amperes"? Well, generally, currents above this threshold are considered to be potentially dangerous and can result in unpleasant shocks. So, it's important to stay within that limit to ensure safety and avoid any unexpected jolts. Let's keep those currents in check!
The statement "a person notices a mild shock if the current along a path through the thumb and index finger of one hand exceeds 80 µA" suggests that exceeding this current threshold may result in a noticeable shock sensation.
To calculate the maximum allowable potential (voltage), we can use Ohm's Law, which states that V = I * R, where V is the voltage, I is the current, and R is the resistance.
Given:
Current (I) = 80 µA = 80 * 10^-6 A
Resistance (R) = 67.7 kΩ = 67.7 * 10^3 Ω
Using Ohm's Law:
V = I * R
Converting the current to amperes:
80 µA = 80 * 10^-6 A
Substituting the values:
V = (80 * 10^-6 A) * (67.7 * 10^3 Ω)
V = 5.416 V
Therefore, the maximum allowable potential (voltage) for a hand with moist skin and a resistance of 67.7 kΩ is approximately 5.416 volts.
If you are getting a different answer, please double-check your calculations to ensure you are using the correct units and values.
To find the maximum allowable potential in volts, we need to use Ohm's Law. Ohm's Law states that the voltage (V) is equal to the current (I) multiplied by the resistance (R): V = I * R.
In this case, we are given the current (I) as 80 ìA (microamperes) and the resistance (R) as 67.7 kÙ (kilohms). However, we need to convert the resistance from kilohms to ohms before we can proceed with the calculation.
1 kilohm (kÙ) = 1000 ohms (Ù)
Therefore, 67.7 kÙ = 67.7 * 1000 Ù = 67700 Ù
Now, we can calculate the voltage using Ohm's Law. We'll convert the current from microamperes to amperes first:
80 ìA (microamperes) = 80 * 10^-6 A (amperes)
V = I * R
V = (80 * 10^-6 A) * 67700 Ù
V = 5.416 V
So, the maximum allowable potential for a hand with moist skin and a resistance of 67.7 kÙ is 5.416 volts.
Regarding why it says "exceeds 80 microamperes," it means that if the current flowing through the thumb and index finger exceeds 80 ìA, a person will experience a mild shock.