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How much work must be done to accelerate a baton from rest to an angular speed of 7.27 rad/s about its center? Consider the baton to be a uniform rod of length 0.529 m and mass 0.478 kg

The moment of inertia of a uniform rod, about a line through the center and perpendicular to the rod, is
I = M L^2/12

The kinetic energy of the rotating rod is (I/2)* w^2

w = 7.27 rad/s L = 0.529 m
M = 0.478 kg

Calculate that kinetic energy. It equals the work required.

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