A sample of helium gas has a volume of 325L at 25C and at 5atm. At what temperature the gas can be compressed at 50atm to a volume of 125L?

(P1V1/T1)=(P2V2/T2)

1146.15

To solve this problem, we can use the combined gas law, which relates the initial and final conditions of a gas sample. The formula for the combined gas law is:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.

Let's assign values to the variables in the formula:

P1 = 5 atm (initial pressure)
V1 = 325 L (initial volume)
T1 = 25°C + 273.15 = 298.15 K (initial temperature in Kelvin, since temperature must be in Kelvin in gas laws)
P2 = 50 atm (final pressure)
V2 = 125 L (final volume)
T2 = ? (final temperature, which we need to find)

Plugging in these values into the formula, we have:

(5 atm * 325 L) / (298.15 K) = (50 atm * 125 L) / (T2)

Now we can solve for T2 by rearranging the equation:

T2 = (50 atm * 125 L * 298.15 K) / (5 atm * 325 L)

T2 ≈ 573.38 K

Therefore, the gas can be compressed at 50 atm to a volume of 125 L at a temperature of approximately 573.38 K.