how many grams of manganese (4) oxide are needed to make 5.6 liters of a 2.1 solution
To determine the number of grams of manganese (IV) oxide needed to make a 2.1% solution in 5.6 liters, we need to follow these steps:
Step 1: Understand the problem.
Manganese (IV) oxide is the solute we are solving for, and 5.6 liters is the volume of the solution. The solution's concentration is given as 2.1%.
Step 2: Convert the given volume to milliliters.
1 liter is equal to 1000 milliliters. Therefore, 5.6 liters can be converted to 5600 milliliters.
Step 3: Calculate the amount of solute needed.
The concentration is given as a percentage, which means 2.1 grams of manganese (IV) oxide are present in 100 milliliters of the solution.
To calculate the grams required for 5600 milliliters:
2.1 grams x (5600 ml / 100 ml) = 2.1 grams x 56 = 117.6 grams
Therefore, you would need approximately 117.6 grams of manganese (IV) oxide to make a 5.6-liter solution with a concentration of 2.1%.