if 3x years from today, Megan will be (3y + 4) times her present age, what is Megan's present age in terms of x and y?

a + 3x = (3y+4)a

a + 3x = 3 y a + 4 a

3x = 3y a + 3 a

x = a (y+1)

a = x/(y+1)

Let's start by setting up an equation to represent the given information.

Megan's present age: x
Megan's age in 3x years: x + 3x = 4x
Megan's age in 3x years is (3y + 4) times her present age: 4x = (3y + 4)x

To find Megan's present age in terms of x and y, we need to solve the equation for x.

Dividing both sides of the equation by x:
4x/x = (3y + 4)x/x
4 = 3y + 4

Subtracting 4 from both sides of the equation:
4 - 4 = 3y + 4 - 4
0 = 3y

We are left with 0 = 3y.

Since there is no information given about y, we cannot determine Megan's present age in terms of x and y using the given equation.

To determine Megan's present age in terms of x and y, we can set up an equation based on the given information.

Let's denote Megan's present age as "a".

According to the given information, 3x years from today, Megan will be (3y + 4) times her present age, which can be written as (a + 3x) = (3y + 4)a.

To solve for Megan's present age, we need to isolate the variable "a" in the equation.

Distribute the "a" on the right side: a + 3x = 3ay + 4a.

Rearrange the equation: a - 3ay - 4a = -3x.

Combine like terms: -3ay - 3a = -3x.

Factor out "a" from the left side: a(-3y - 3) = -3x.

Divide both sides by (-3y - 3): a = -3x / (-3y - 3).

The expression -3x / (-3y - 3) represents Megan's present age in terms of x and y.