A complex was formed between Ni (II) and 1-cyclopentene-1-dithiocarboxylic acid (CDA). The measurements were made at 530 nm in 1.00-cm cell. Find the formula of the complex.

C(CDA)=1.00x10^-3
C(Ni)-1.00x10^-3

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To determine the formula of the complex formed between Ni (II) and 1-cyclopentene-1-dithiocarboxylic acid (CDA), we can use the Beer-Lambert law.

The Beer-Lambert law relates the concentration of a solution to the amount of light absorbed by it. It can be expressed as:

A = εcl

Where:
A is the absorbance of the solution at a specific wavelength
ε is the molar absorptivity (also known as the molar extinction coefficient), which represents the ability of a substance to absorb light at a specific wavelength
c is the concentration of the absorbing species in the solution
l is the path length (in this case, 1.00 cm)

Since we are given the concentration of CDA (C(CDA) = 1.00x10^-3) and the concentration of Ni (C(Ni) = 1.00x10^-3), we need to determine the absorbance (A) at 530 nm.

The molar absorptivity (ε) for the complex at 530 nm can be determined experimentally or provided in the question. Let's assume an arbitrary value of ε = 1.00 L/mol/cm for demonstration purposes. Note that in reality, the molar absorptivity value varies depending on the specific complex.

Using the Beer-Lambert law, we can rearrange the equation to solve for the concentration (c) of the absorbing species:

c = A / (εl)

Plugging in the values, we have:

c = A / (1.00 L/mol/cm × 1.00 cm)
c = A / 1.00 L/mol

Given that C(CDA) = 1.00x10^-3, and C(Ni) = 1.00x10^-3, we can express the total concentration of the complex as:

C(Total) = C(CDA) + C(Ni)

Assuming the complex is formed via a 1:1 stoichiometry between Ni (II) and CDA, we have:

C(Total) = 1.00x10^-3 + 1.00x10^-3
C(Total) = 2.00x10^-3

Therefore, the formula of the complex is NiCDA2.