A truck enters a highway driving 60mph. A car enter the highway at the same place 14 minutes later and drives 66mph in the dame direction. From the time the car enters the highway, how long will it take the car to pass th truck?
d1 = d2,
14min = 14/60 = 0.2333h.
60t = 66(t - 0.2333),
60t = 66t - 15.4
60t - 66t = -15.4,
-6t = -15.4,
t = 2.57h.
t - 0.2333 = 2.57 - 0.2333 = 2.33h to
catch up.
To find out how long it will take for the car to pass the truck, we first need to determine the distance the truck will have traveled by the time the car enters the highway.
The truck is traveling at a speed of 60 mph. We know that speed is defined as distance divided by time. Let's assume 't' hours is the time it takes for the car to pass the truck. Therefore, in 't' hours, the truck would have traveled a distance of 60t miles.
Now, we need to convert the given delay of 14 minutes into hours. Since there are 60 minutes in an hour, 14 minutes is equivalent to 14/60 hours, or 0.233 hours.
Since the car enters the highway 14 minutes (0.233 hours) after the truck, the car will have to travel the same distance as the truck plus the distance it takes to pass the truck. In other words, the car will have to travel a distance of 60t miles.
The car is traveling at a speed of 66 mph. To find out how long it will take for the car to pass the truck, we set up the following equation:
60t + 66t = 60t + 66t
By combining like terms, we get:
126t = 60t + 66t
Simplifying further, we have:
126t = 126t
Since both sides of the equation are equal, the car will take the same amount of time as the truck to reach the passing point. Therefore, the answer to the question is that it will take 't' hours for the car to pass the truck after it enters the highway.