Compute the de Broglie wavelength associated with a ping-pong ball that is moving with a velocity of 4 meters per second. The mass of the ping-pong ball is 20 grams
isn't wavelength= plancksconstant/mv ?
To compute the de Broglie wavelength associated with a ping-pong ball, we can use the de Broglie wavelength formula:
λ = h / p
Where:
λ is the de Broglie wavelength
h is the Planck constant (6.626 x 10^-34 J.s)
p is the momentum of the ping-pong ball
The momentum (p) of an object can be calculated using the equation:
p = m * v
Where:
m is the mass of the ping-pong ball
v is the velocity of the ping-pong ball
First, let's convert the mass from grams to kilograms:
mass = 20 grams = 20 / 1000 = 0.02 kg
Now, we can calculate the momentum (p):
p = 0.02 kg * 4 m/s = 0.08 kg.m/s
Finally, we can use the de Broglie wavelength formula to compute the de Broglie wavelength (λ):
λ = 6.626 x 10^-34 J.s / 0.08 kg.m/s
Calculating the result:
λ = 8.283 x 10^-33 m
Therefore, the de Broglie wavelength associated with the ping-pong ball is approximately 8.283 x 10^-33 meters.