Compute the de Broglie wavelength associated with a ping-pong ball that is moving with a velocity of 4 meters per second. The mass of the ping-pong ball is 20 grams

isn't wavelength= plancksconstant/mv ?

To compute the de Broglie wavelength associated with a ping-pong ball, we can use the de Broglie wavelength formula:

λ = h / p

Where:
λ is the de Broglie wavelength
h is the Planck constant (6.626 x 10^-34 J.s)
p is the momentum of the ping-pong ball

The momentum (p) of an object can be calculated using the equation:

p = m * v

Where:
m is the mass of the ping-pong ball
v is the velocity of the ping-pong ball

First, let's convert the mass from grams to kilograms:

mass = 20 grams = 20 / 1000 = 0.02 kg

Now, we can calculate the momentum (p):

p = 0.02 kg * 4 m/s = 0.08 kg.m/s

Finally, we can use the de Broglie wavelength formula to compute the de Broglie wavelength (λ):

λ = 6.626 x 10^-34 J.s / 0.08 kg.m/s

Calculating the result:

λ = 8.283 x 10^-33 m

Therefore, the de Broglie wavelength associated with the ping-pong ball is approximately 8.283 x 10^-33 meters.