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How many atoms of carbon are present in
31.4 g of a compound that is 16.2% carbon, by weight?
Answer in units of atoms.

  • Chemistry -

    The mass is 31.4 g and it is 16.2%C; therefore, g C = 31.4*0.162 = ??
    moles C = ??g/molar mass C = xx moles C..
    1 mole of C atoms contains 6.022E23 atoms and you have xx moles C. _____ = # C atoms.

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