posted by Jackson .
How many atoms of carbon are present in
31.4 g of a compound that is 16.2% carbon, by weight?
Answer in units of atoms.
The mass is 31.4 g and it is 16.2%C; therefore, g C = 31.4*0.162 = ??
moles C = ??g/molar mass C = xx moles C..
1 mole of C atoms contains 6.022E23 atoms and you have xx moles C. _____ = # C atoms.