How much lead (Pb) is in 3.01 × 10^12 atoms of lead?
Answer in units of mol.
3.01E12 atoms x (1 mol atoms/6.022E23 atoms) = ?? mole.
To calculate the amount of lead (Pb) in 3.01 × 10^12 atoms, we need to convert the number of atoms to moles.
The conversion factor needed for this calculation is Avogadro's number, which defines the number of atoms in one mole of any substance. Avogadro's number is approximately 6.022 × 10^23 atoms per mole.
We can use this conversion factor to solve the problem:
1 mol Pb = 6.022 × 10^23 atoms Pb
To find the number of moles of Pb in 3.01 × 10^12 atoms Pb, we will set up a proportion.
(3.01 × 10^12 atoms Pb) × (1 mol Pb / 6.022 × 10^23 atoms Pb) = x mol Pb
Now, we can calculate the value of x:
x = (3.01 × 10^12) / (6.022 × 10^23)
x ≈ 4.995 × 10^(-12) mol Pb
Therefore, there is approximately 4.995 × 10^(-12) moles of lead (Pb) in 3.01 × 10^12 atoms of lead.