iF 23.74Ml OF 0.01470m nAoh are required to completely neutrize 25.00mL of gastric juice,calculate the concentration of the hydrochloric acid(in g/L )in the stomach gastric juice.show steps and calculations

You need one mole of NaOH to neutralize one mole of HCl.

You require 0.02374 L x 0.0147 mole/L = 3.49 *10^-4 moles of NaOH

That many moles of HCl have a mass of 1.274*10^-2 g

The concentration is
(1.274*10^-2 g)/(25*10^-3 L)
= 0.510 g/L

23.73*.01470=25*M

solve for M, the molarity of the gastric juice.

To calculate the concentration of hydrochloric acid (HCl) in the stomach gastric juice, we can use the concept of stoichiometry, which involves the balanced chemical equation for the neutralization reaction between HCl and NaOH:

HCl + NaOH → NaCl + H2O

First, we need to determine the number of moles of NaOH used to neutralize the gastric juice. We can do this using the given volume (23.74 mL) and concentration (0.01470 M) of NaOH:

Step 1: Convert milliliters (mL) to liters (L):
Volume of NaOH = 23.74 mL = 23.74/1000 L = 0.02374 L

Step 2: Calculate the number of moles of NaOH:
Moles of NaOH = Volume (in L) × Concentration (in mol/L)
Moles of NaOH = 0.02374 L × 0.01470 mol/L = 0.000348778 mol

Since the neutralization reaction has a 1:1 stoichiometric ratio between NaOH and HCl, the number of moles of HCl in the gastric juice is also 0.000348778 mol.

Next, we need to determine the concentration of hydrochloric acid in the gastric juice. To do this, we need to know the volume of the gastric juice being neutralized.

Given volume of gastric juice = 25.00 mL = 25.00/1000 L = 0.02500 L

Step 3: Calculate the concentration of HCl in mol/L:
Concentration of HCl = Moles of HCl / Volume of Gastric Juice (in L)
Concentration of HCl = 0.000348778 mol / 0.02500 L = 0.01395112 mol/L

Finally, to convert the concentration of HCl to grams per liter (g/L), we need to determine the molar mass of HCl, which is the sum of the atomic masses of hydrogen (H) and chlorine (Cl):

Molar mass of HCl = (1.00784 g/mol) + (35.453 g/mol) = 36.46084 g/mol

Step 4: Convert the concentration of HCl to grams per liter (g/L):
Concentration of HCl (in g/L) = Concentration of HCl (in mol/L) × Molar mass of HCl (in g/mol)
Concentration of HCl (in g/L) = 0.01395112 mol/L × 36.46084 g/mol ≈ 0.509 g/L

Therefore, the concentration of hydrochloric acid (HCl) in the stomach gastric juice is approximately 0.509 g/L.