Three point charges lie along the x-axis: q1 at x=15m has a charge of 2.2 x 10^-9C, q2 at x=2.0m has a charge of 5.4 x 10^-9C, q3 at x=0 has a charge of 3.5 x 10^-9C. What is the net force on q3?

Three point charges lie along the x-axis: q1 at x=15m has a charge of 2.2 x 10^-9C, q2 at x=2.0m has a charge of 5.4 x 10^-9C, q3 at x=0 has a charge of 3.5 x 10^-9C. What is the net force on q3?

To find the net force on q3, we need to calculate the individual forces between q3 and q1, and between q3 and q2. The net force on q3 will be the vector sum of these two forces.

The formula for the force between two point charges is given by Coulomb's Law:

F = (k * |q1 * q2|) / r^2

Where:
F is the force between the charges,
k is Coulomb's constant (k = 9.0 x 10^9 Nm^2/C^2),
|q1| and |q2| are the magnitudes of the charges,
r is the distance between the charges.

Let's calculate the forces between q3 and q1, and between q3 and q2.

Force between q3 and q1:
|q3| = 3.5 x 10^-9 C
|q1| = 2.2 x 10^-9 C
r1 = distance between q3 and q1 = 15 m

Using Coulomb's Law, we can calculate the force between q3 and q1:
F1 = (9.0 x 10^9 Nm^2/C^2) * (|q3| * |q1|) / r1^2

Force between q3 and q2:
|q2| = 5.4 x 10^-9 C
r2 = distance between q3 and q2 = 2.0 m

Using Coulomb's Law, we can calculate the force between q3 and q2:
F2 = (9.0 x 10^9 Nm^2/C^2) * (|q3| * |q2|) / r2^2

Now, we need to calculate the net force on q3 by finding the vector sum of F1 and F2:
Net Force on q3 = F1 + F2

Solving these equations will give us the net force on q3.