What mass of sodium iodide (NaI) is contained in 135 mL of a 7.0% (m/v) soulution?
Mike tyson
To determine the mass of sodium iodide (NaI) in a given solution, we need to utilize the concept of percent mass/volume concentration.
The concentration is given as 7.0% (m/v), which means that for every 100 mL of the solution, there are 7.0 grams of NaI.
To find the mass of NaI in the solution, follow these steps:
Step 1: Convert the given volume from milliliters (mL) to liters (L).
Volume = 135 mL = 135/1000 = 0.135 L
Step 2: Calculate the mass of NaI using the percent concentration.
Mass of NaI = Volume × Concentration
Mass of NaI = 0.135 L × 7.0% = 0.135 L × 0.07 = 0.00945 kilograms (kg)
Finally, convert the mass into grams by multiplying by 1000:
Mass of NaI = 0.00945 kg × 1000 = 9.45 grams (g)
Therefore, there are approximately 9.45 grams of sodium iodide (NaI) in 135 mL of a 7.0% (m/v) solution.
7% NaI m/v means 7g NaI/100 mL soln.
Therefore, a 135 mL sample contains
7g x (135/100) = ??