What is the total molar concetration of all the ions in 0.015 M solutions of the following salts in water?

.015 M KCl

.015 M CuSO4

.015 M CaCl2

KCl ionizes 100%; therefore,

KCl ==> K^+ + Cl^-
There is 1 K in KCl so (K^+) = 0.015M.
There is 1 Cl in KCl so (Cl^-) = 0.015
Total concn ions = 0.015 + 0.015 = ??

CuSO4 ==> Cu^+2 + SO4^-2

CaCl2 ==> Ca^+2 + 2Cl^-

Someone will check your answers if you wish to post them.

To find the total molar concentration of ions in a solution, you need to consider the dissociation of each salt into its individual ions.

1. KCl:
When KCl dissolves in water, it dissociates into K+ and Cl- ions. Since the molar concentration of KCl is 0.015 M, the molar concentration of both K+ and Cl- ions will also be 0.015 M.

2. CuSO4:
CuSO4 dissociates into Cu2+ and SO4^2- ions. Similarly, since the molar concentration of CuSO4 is 0.015 M, the molar concentration of both Cu2+ and SO4^2- ions will be 0.015 M.

3. CaCl2:
CaCl2 dissociates into Ca2+ and 2Cl- ions. Since the molar concentration of CaCl2 is 0.015 M, the molar concentration of Ca2+ will be 0.015 M as well. However, we need to consider the Cl- ions twice, as there are two Cl- ions produced for each molecule of CaCl2. Therefore, the molar concentration of Cl- ions will be 2 × 0.015 M = 0.03 M.

In summary:
- The total molar concentration of ions in a 0.015 M KCl solution is 0.015 M K+ and 0.015 M Cl-.
- The total molar concentration of ions in a 0.015 M CuSO4 solution is 0.015 M Cu2+ and 0.015 M SO4^2-.
- The total molar concentration of ions in a 0.015 M CaCl2 solution is 0.015 M Ca2+ and 0.03 M Cl-.