posted by NY-Calc
Let f(x) = 3x^2 - 2x + 1
a) write an equation of the line going through the points (1, f(1)), and (2, f(2)).
b) Find a point on the graph of f where the tangent line to the graph has the same slope as the line in part (a). Write the equation of the tangent line at that point.
I got the answer to part A. For part b, I'm confused...isn't the slope of the tangent line -1/slope of normal line?
for part a) i got y = 7x -5