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The peak value of the ac current in a circuit is 6.0 A, and peak value of the ac voltage applied to the circuit is 8.9 V. What is the average power P delivered to the circuit?


    The average power dissipated in a 47-Ù resistor is 5.9 W. What is the peak value I0 of the ac current in the resistor?


    Average power is half the product of peak voltage and peak current.

    For your second question

    Avg. Power = (1/2)Io^2*R

    Solve for Io

    Peak voltages and currents are usually not used in AC calculations; instead, r.m.s. (root mean square) values are used. They are 0.707 (1/sqrt2) times the peak value

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