Lisa will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of $53.98 and costs an additional $0.15 per mile driven. The second plan has an initial fee of $67.98 and costs an additional $0.10 per mile driven. How many miles would Lisa need to drive for the two plans to cost the same?
53.98 + .15M = 67.98 + .10M
Solve for M
54.13 68.08
280
To find the number of miles Lisa would need to drive for the two plans to cost the same, we can set up an equation. Let's denote the number of miles as 'x'.
For the first plan, the cost is given by:
Cost = Initial fee + (Additional cost per mile * Number of miles)
Cost = $53.98 + ($0.15 * x)
For the second plan, the cost is given by:
Cost = Initial fee + (Additional cost per mile * Number of miles)
Cost = $67.98 + ($0.10 * x)
To find the number of miles for the two plans to have the same cost, we set the two equations equal to each other and solve for 'x':
$53.98 + ($0.15 * x) = $67.98 + ($0.10 * x)
Now, let's solve for 'x':
$0.15 * x - $0.10 * x = $67.98 - $53.98
$0.05 * x = $14
x = $14 / $0.05
x = 280
So, Lisa would need to drive 280 miles for the two plans to cost the same.