Hitomi has a total of 30 red and blue bowling balls at her bowling alley. Each red ball weighs 8 lb. Each blue ball weighs 9 lb. If the total mass of the blue balls is 49 lb. heavier than the total mass of the red balls, how many red balls does she have?
what i did was i did=
x= # of red balls
30-x= # of blue balls
9(30-x)= 8 x + 49
and you get 13 red balls
This is hard
First, I turned this into an equation:
9(30-x)=8x+49
30-x is the blue bowling balls, and x is the red bowling balls. Heres how I solved it:
equation:
9(30-x)=8x+49
rearrange the equation:
9(-x+30)=8x+49
get rid of the 270:
-9x+270=8x+49
-270 -270
get rid of the 8x:
-9x=8x-270
-8x -8x
divide by -17
-17= -270
/-17 /-17
solution:
x=13
Hope this helps!
I have nooo idea
Let x = # red balls and 30-x = # blue balls
9(30-x) = 8x + 49
Solve for x.
To solve this problem, let's assume the number of red balls is represented by "r" and the number of blue balls is represented by "b."
First, we know that the total number of balls is 30, so we have the equation: r + b = 30.
Next, we can set up an equation based on the given information about the total mass of the red and blue balls. Since each red ball weighs 8 lb and each blue ball weighs 9 lb, the total mass of the red balls can be calculated as 8r, and the total mass of the blue balls can be calculated as 9b. We are also given that the total mass of the blue balls is 49 lb heavier than the total mass of the red balls. So, we have the equation: 9b = 8r + 49.
Now, we can solve this system of equations to find the values of r and b.
Let's solve the first equation for r, by subtracting b from both sides: r = 30 - b.
Substituting this value of r in the second equation, we get: 9b = 8(30 - b) + 49.
Expanding and simplifying the equation: 9b = 240 - 8b + 49.
Combining like terms: 9b + 8b = 240 + 49.
Simplifying further: 17b = 289.
Finally, solving for b: b = 289 / 17 = 17.
Now we know that there are 17 blue balls.
Substituting this value of b in the first equation to find r: r = 30 - b = 30 - 17 = 13.
Therefore, Hitomi has 13 red balls.